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11x^2+17x-10=0
a = 11; b = 17; c = -10;
Δ = b2-4ac
Δ = 172-4·11·(-10)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-27}{2*11}=\frac{-44}{22} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+27}{2*11}=\frac{10}{22} =5/11 $
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